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What is the value of 5 \(cos^{-1}\frac{1}{2} + 7 sin^{-1}(\frac{-1}{2})\) ?(a) –\(\frac{π}{2}\)(b) π(c) \(\frac{π}{2}\)(d) \(\frac{17π}{6}\)The question was asked in a national level competition.The question is from Inverse Trigonometric Functions Basics topic in chapter Inverse Trigonometric Functions of Mathematics – Class 12 |
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Answer» RIGHT choice is (c) \(\frac{π}{2}\) To explain: \(cos^{-1}(\frac{1}{2})=\frac{π}{3} and SIN^{-1}(-\frac{1}{2})=-\frac{π}{6}\) ∴ 5 \(cos^{-1}\frac{1}{2}+7 sin^{-1}(-\frac{1}{2}) =5(\frac{π}{3})+7(-\frac{π}{6})\) =\(\frac{5π}{3}-\frac{7π}{6}=\frac{10π-7π}{6}=\frac{3π}{6}=\frac{π}{2}\) |
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