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What is the value of cos(tan^-1(\(\frac{4}{5}\)))?(a) \(\frac{5}{4}\)(b) \(\frac{5}{\sqrt{41}}\)(c) \(\frac{\sqrt{41}}{5}\)(d) \(\frac{4}{5}\)The question was asked by my college director while I was bunking the class.Origin of the question is Properties of Inverse Trigonometric Functions in portion Inverse Trigonometric Functions of Mathematics – Class 12 |
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Answer» RIGHT choice is (B) \(\frac{5}{\sqrt{41}}\) EXPLANATION: From ∆ABC, we get tan^-1(\(\frac{4}{5}\))=cos^-1(\(\frac{5}{\sqrt{41}}\)) cos(tan^-1(\(\frac{4}{5}\))=cos(cos^-1(\(\frac{5}{\sqrt{41}}\))) =\(\frac{5}{\sqrt{41}}\) |
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