What is the value of rate constant k if the value of the activation energy Ea and the frequency factor A are 49 kJ / mol and 9 × 10^10 s^-1 respectively? (T = 313 K)(a) 6 × 10^2s^-1(b) 9 × 10^2s^-1(c) 6 × 10^-2s^-1(d) 3 × 10^2s^-1This question was addressed to me during an internship interview.I would like to ask this question from Chemical Kinetics topic in chapter Chemical Kinetics of Chemistry – Class 12

What is the value of rate constant k if the value of the activation en

1.	What is the value of rate constant k if the value of the activation energy Ea and the frequency factor A are 49 kJ / mol and 9 × 10^10 s^-1 respectively? (T = 313 K)(a) 6 × 10^2s^-1(b) 9 × 10^2s^-1(c) 6 × 10^-2s^-1(d) 3 × 10^2s^-1This question was addressed to me during an internship interview.I would like to ask this question from Chemical Kinetics topic in chapter Chemical Kinetics of Chemistry – Class 12
Answer» Right answer is (a) 6 × 10^2s^-1 The BEST explanation: GIVEN, Ea = 49 kJ / mol^-1 T = 313 K A = 9 × 10^2 s^-1 R = 8.314 J K^-1 mol^-1 log k = – Ea / (2.303 RT) + log A log k = – 49000 / (2.303 × 8.314 × 313) + log 9 × 10^10 log k = 2.77843 k= antilog (2.77843) k = 6 × 10^2 s^-1.

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