What is the value of y so that the line through (3, y) and (2, 7) is p

1.	What is the value of y so that the line through (3, y) and (2, 7) is parallel to the line through (– 1, 4) and (0, 6) ?
Answer» We have given coordinates of two lines (3, y) and (2, 7), (– 1, 4) and (0, 6) To Find: Value of y? The concept used: Slopes of the parallel line are always equal. The formula used: The slope of line = \(\frac{y_2-y_1}{x_2-x_1}\) Now, The slope of the line whose coordinates are (3, y) and (2, 7). M₁ = \(\frac{7-y}{2-3}\) …… (1) And, Now, The slope of the line whose coordinates are (– 1, 4) and (0, 6). M₂ = \(\frac{6-4}{0-(-1)}\) M₂ = \(\frac{2}{1}\)…… (2) On equating the equation (1) and (2), we get \(\frac{7-y}{2-3}=\frac{2}{1}\) 7 – y = 2(– 1) – y = – 2 – 7 Y = 9 Hence, The value of y is 9.

What is the value of y so that the line through (3, y) and (2, 7) is parallel to the line through (– 1, 4) and (0, 6) ?

Answer»

We have given coordinates of two lines (3, y) and (2, 7), (– 1, 4) and (0, 6)

To Find: Value of y?

The concept used: Slopes of the parallel line are always equal.

The formula used: The slope of line = \(\frac{y_2-y_1}{x_2-x_1}\)

Now, The slope of the line whose coordinates are (3, y) and (2, 7).

M₁ = \(\frac{7-y}{2-3}\) …… (1)

And, Now, The slope of the line whose coordinates are (– 1, 4) and (0, 6).

M₂ = \(\frac{6-4}{0-(-1)}\)

M₂ = \(\frac{2}{1}\)…… (2)

On equating the equation (1) and (2), we get

\(\frac{7-y}{2-3}=\frac{2}{1}\)

7 – y = 2(– 1)

– y = – 2 – 7

Y = 9

Hence, The value of y is 9.