1.

What is the volume occupied by 30 g of neon gas at 67^(@)C and750 mm of Hg?

Answer»

Solution :According to theideal gas equation:
PV = nRT(1)
n= number of moles = weight/molecular weight = 30/20
Pressure = (750/760) atm [1 atm = 760 MM of Hg]
T = (273+67) K = 340K
From equation (1),
V = nRT/P
`V = 30/20 xx(0.0821 xx340)/((750//760))((g xx"L.atm/k.mol "xxK)/("g/mol "xx "atm"))=42.43 L`


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