1.

What mass of `Ra^(226)` whose `t_(1//2) = 1620` years will give the activity of 1 millicurie?

Answer» Activity `= (0.692)/(t_(1//2)) xx (W)/("Atomic weight") xx 6.023 xx 10^(23)`
`3.7 xx 10^(7) = (0.693)/(226) xx 6.023 xx 10^(23)`
or `W = 10^(-3) g`


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