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What number should be added to \(\frac{-5}{11}\) so as to get \(\frac{26}{33}\) ? |
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Answer» Suppose x be the rational number to be added to \(\frac{-5}{11}\) to get \(\frac{26}{33}\) Then, \(\frac{-5}{11}\)+x = \(\frac{26}{33}\) x = \(\frac{26}{33}\)+\(\frac{5}{11}\) x = \(\frac{26\times 1+5\times 3}{33}\) x = \(\frac{26+15}{33}\) x = \(\frac{41}{33}\) Therefore, The required number x = \(\frac{41}{33}\) |
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