1.

What should be added to \(\frac{2}{3}+\frac{3}{5}\) to get \(\frac{-2}{15}\) ?

Answer»

Let us consider a number as x to be added to (2/3 + 3/5) to get -2/15
\(x+(\frac{2}{3}+\frac{3}{5})=\frac{-2}{15}\\=\frac{(15x+2\times5+3\times3)}{15}\\=\frac{-2}{15}\\15x+10+9=-2\\15x=-2-19\\x=\frac{-21}{15}\\=\frac{-7}{5}\)

\(\therefore\)the required number is \(\frac{-7}{5}\)



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