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What should be added to \(\frac{7}{12}\) to get \(\frac{-4}{15}\,?\)A. \(\frac{17}{20}\)B. \(\frac{-17}{20}\)C. \(\frac{7}{20}\)D. \(\frac{-7}{20}\) |
Answer» Let the number added be x. Then, \(\frac{7}{12}+\text{x}=\frac{-4}{15}\) \(\Rightarrow\) \(\text{x}=\frac{-4}{15}-\frac{7}{12}\) \(=\frac{-4\times4-7\times5}{60}\) \(=\frac{-16-35}{8}\) \(=\frac{-51}{60}=\frac{-51\div3}{60\div3}=\frac{-17}{20}\) |
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