1.

What should be added to \(\frac{7}{12}\) to get \(\frac{-4}{15}\,?\)A. \(\frac{17}{20}\)B. \(\frac{-17}{20}\)C. \(\frac{7}{20}\)D. \(\frac{-7}{20}\)

Answer»

Let the number added be x.

Then,

\(\frac{7}{12}+\text{x}=\frac{-4}{15}\)

\(\Rightarrow\) \(\text{x}=\frac{-4}{15}-\frac{7}{12}\)

\(=\frac{-4\times4-7\times5}{60}\)

\(=\frac{-16-35}{8}\)

\(=\frac{-51}{60}=\frac{-51\div3}{60\div3}=\frac{-17}{20}\)



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