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What should be added to \(\frac{-7}{8}\) so as to get \(\frac{5}{9}\)? |
Answer» Let the number x to be added to -7/8 to get 5/9 \(\frac{-7}{8}+x=\frac{5}{9}\\\frac{(-7+8x)}{8}=\frac{5}{9}\\(-7+8x)\times9=5\times8\\-63+72x=40\\72x=40+73\\x=\frac{103}{72}\) \(\therefore\) the required number is \(\frac{103}{72}\) |
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