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What should be subtracted from (\(\frac{3}{4}\)-\(\frac{2}{3}\)) to get \(\frac{-1}{6}\) ? |
Answer» Let the number be x It is given that, (\(\frac{3}{4}\)-\(\frac{2}{3}\)) - x = \(\frac{-1}{6}\) - x + [ \(\frac{3\times 3}{4\times 3}\) - \(\frac{2\times 4}{4\times 3}\)] = \(\frac{-1}{6}\) - x + [\(\frac{9}{12}\)-\(\frac{8}{12}\)] = \(\frac{-1}{6}\) \(\frac{-12x+9-8}{12}\) = \(\frac{-1}{6}\) -12x-1 = -2-12x = -2-1-12x = -3 x = \(\frac{-3}{-12}\) x = \(\frac{1}{4}\) |
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