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What should be the ratio of the velocity of `1CH_(4) and O_(2)` molecules so that they are associated with de Broglie wave of equal wavelegth ? |
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Answer» According to de Broglie equation For methane `(CH_(4))` `lambda _(CH_4) = (h)/(m_(CH_4) xx v_(CH_4))` For oxygen `(O_(2))` `lambda_(O_2) = (h)/(m_(O_2) xx v_(O_2))` since the wavelength of `CH_(4)` and `O_(2)` sould be equal `lambda _(CH_4) = lambda _(O_2)` `or (h)/(m_(CH_4) xx v_(CH_4)) = (h)/(m_(O_2) xx vO_(2))` `m_(CH_4) xx vCH_(4) = m_(O_2) xx vO_(2)` `or (vCH_4)/(v_(O_2)) = (m_(O_2))/(m_(CH_4)) = (32)/(16) = 2` |
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