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What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition `n = 4` to `n=2` of ` He^(o+)` spectrum? |
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Answer» For ` He^+ : 1/ (lambda) = R _H xx Z^2 [1/n_1^2 - 1/n_2^2]`, ` 1/ (lambda)R_H xx 4 [ 1/2^2 - 1/4^2 ] ( :. Fo r He Z=2) …(1)` For H -atom `: (1)/ (lambda)R_H [1/n_1^2 - 1/n_2^2]` …(2) For same ` (lambda)`,by eqs. (1) and (2), ` therefore 2^2 [ 1/2^2 - 1/4^2] = [ 1/n_1^2 - 1/n_2^2] , [ 1/1^2 - 1/2^2] = [ 1/n_1^2 - 1/n_2^2] ` `therefore n_1 = 1 "and " n_2 =2`. |
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