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What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition `n=4` to `n=2` of `He^(+)` spectrum ?A. `n_(1) = 1, n_(2) = 2`B. `n_(1) = 2, n_(2) = 3`C. `n_(1) = 3, n_(2) = 2`D. `n_(1) =2, n_(2) = 4` |
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Answer» Correct Answer - A `R xx Z^(2) [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))] = R [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]` |
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