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What volume of 0.45 M H_(3)PO_(4) is needed to neutralise 60 mL of 0.60 N NaOH solution ? (Assume that there is a complete ionisation of acid and base) |
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Answer» Solution :(i) BALANCED equations and comparison of equivalents (ii) BASICITY of acid (iii) calculation of NORMALITY of `H_(3)PO_(4)` (iv) calculation of number of equivalents of base (v) calculation of volume of acid required based on normality of acid and number of equivalents of base (vi) 26.6 ml |
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