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What will be de-Broglie wavelength of an electron moving with a velocity of `1.2xx10^5 "ms"^(-1)`A. `6.071xx10^(-9)`B. `3.133xx10^(-37)`C. `6.626xx10^(-9)`D. `6.018xx10^(-7)` |
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Answer» Correct Answer - A `lambda=h/p , p=mv` `lambda=h/"mv"=(6.62xx10^(-34))/(9.1xx10^(-31)xx1.2xx10^5)` `lambda=6.071xx10^(-9)`m |
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