1.

What will be de-Broglie wavelength of an electron moving with a velocity of `1.2xx10^5 "ms"^(-1)`A. `6.071xx10^(-9)`B. `3.133xx10^(-37)`C. `6.626xx10^(-9)`D. `6.018xx10^(-7)`

Answer» Correct Answer - A
`lambda=h/p , p=mv`
`lambda=h/"mv"=(6.62xx10^(-34))/(9.1xx10^(-31)xx1.2xx10^5)`
`lambda=6.071xx10^(-9)`m


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