What will be the atomic number of an atom if its electronic configuration is `(n - 2)s^(2) (n - 1)s^(a) p^(b) ms^(2)p^(2)` where `n = 3, a= 2` and `b= 6` ?

What will be the atomic number of an atom if its electronic configurat

1.	What will be the atomic number of an atom if its electronic configuration is `(n - 2)s^(2) (n - 1)s^(a) p^(b) ms^(2)p^(2)` where `n = 3, a= 2` and `b= 6` ?
Answer» The electronic configuraqtion of nitrogen atom is `(n-2)s^(2)(n-1)s^(a)p^(b)ms^(2)p^(2)`where` n= 3,a= 2` and `b= 6` ON substituting all the velues in the configuration we get `(3 - 2)s^(2) (3 - 1)s^(2)p^(6)3s^(2)p^(2) = 1s^(2)2s^(2)2p^(6)3s^(2)3p^(2)3p^(2) = 14` Thus the atomic number of the atom is `14`

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What will be the atomic number of an atom if its electronic configuration is `(n - 2)s^(2) (n - 1)s^(a) p^(b) ms^(2)p^(2)` where `n = 3, a= 2` and `b= 6` ?

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