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What will be the difference in mass number if the number of neutrons halved and the number of electrons doubled in `._(6)^(12)C` |
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Answer» Mass no is the sum of protons and neutraons `{:(ln ._(6)^(12)C,"Initial","Final"),("protons":,6,6),("Neutrons":,6,3),("mass no":,12,9):}` Hence the decrease in mass no is `25.0%` |
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