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What will be the kinetic energy and total eknergy charge of an in H atom if the atom emit a photon of wavelength `4860 Å`? |
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Answer» The energy released is `E = (hc)/(lambda) = ((6.625 xx 10^(-34) Js) xx ( 3 xx 10^(8) ms^(-1)))/((4860 xx 10^(-10)m))` `= 4.09 xx 10^(-19) J` 1:. Total energy charge `= 4.09 xx 10^(-19) J` :. Total energy due to released of photon = gain in kinetic energy `= 4.09 xx 10^(-19) J` |
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