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What will be the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 150,000 in 500 mL of water at `37^@C` ?A. 30.96 PaB. 34.36 PaC. 68.72 PaD. 48.25 Pa |
Answer» Correct Answer - B No. of moles of polymer =`1/(150,000)``pi=CRT = n/VRT` `pi=1/(150,000)xx(8.314xx10^3xx310)/0.5=34.36` Pa (R=`8.314xx10^3` Pa L `K^(-1) mol^(-1)`) |
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