1.

What will be the value of acceleration due to gravity on the surface of the earth if the radius of the earth suddenly decreases to 60% of its present value, keeping the mass of the earth unchanged?(a) 9.81 m/s^2(b) 5.89 m/s^2(c) 16.35 m/s^2(d) 27.25 m/s^2This question was addressed to me in my homework.My question is from Universal Law of Gravitation in portion Gravitation of Physics – Class 11

Answer»

The correct option is (d) 27.25 m/s^2

For explanation I WOULD say: From Newton’s LAW of gravitation, we have;

g = (G*M1)/R^2

Since the radius is REDUCED to 60% of its original value;

The NEW radius R’ = 0.6 x R

Therefore;

g’ = (G*M1)/(0.6*R) ^2

g’ = g/(0.6) ^2

= 9.81 / (0.6 x 0.6)

g’ = 27.25 m/s^2.



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