What would be the magnitude of the acceleration due to gravity on the surface of the earth if the density of the earth increased by 3 times and the radius remained the same?(a) 9.81 m/s^2(b) 12.26 m/s^2(c) 15.33 m/s^2(d) 29.43 m/s^2The question was posed to me in an internship interview.Query is from Acceleration due to Gravity of the Earth in portion Gravitation of Physics – Class 11

What would be the magnitude of the acceleration due to gravity on the

1.	What would be the magnitude of the acceleration due to gravity on the surface of the earth if the density of the earth increased by 3 times and the radius remained the same?(a) 9.81 m/s^2(b) 12.26 m/s^2(c) 15.33 m/s^2(d) 29.43 m/s^2The question was posed to me in an internship interview.Query is from Acceleration due to Gravity of the Earth in portion Gravitation of Physics – Class 11
Answer» The CORRECT choice is (d) 29.43 m/s^2 The explanation is: g = (GM1)/R^2; M1 = Mass of the earth R = Radius of the earth Since the radius is the same, the volume would remain constant. Density = mass/volume Since density is increased 3 times and volume is the same, this implies that mass is increased 3 times. We know; g = 9.81 m/s^2 New mass = 3 X M1 Therefore, new ACCELERATION; 3 x (GM1)/R^2 = 3X g = 3 x 9.81 = 29.43 m/s^2.

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