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1. |
When `1.80g` glucose dissolved in `90g of H_(2)O`,the mole fraction of glucose isA. `0.00399`B. `0.00199`C. `0.0199`D. `0.998` |
Answer» Correct Answer - B Mole fraction of glucose `(n)/(n+N)=(0.01)/(0.01+5)` `0.00199` |
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