1.

When `1.80g` glucose dissolved in `90g of H_(2)O`,the mole fraction of glucose isA. `0.00399`B. `0.00199`C. `0.0199`D. `0.998`

Answer» Correct Answer - B
Mole fraction of glucose `(n)/(n+N)=(0.01)/(0.01+5)`
`0.00199`


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