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When `3`g of a novolatile solute is dissolved in 50 g of water , the relative lowering of vapour pressure observed is `0.018 Nm^(-2)`. Molecular weight of the substances isA. `60`B. `30`C. `40`D. `120` |
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Answer» Correct Answer - A `(P_(A)^(@)-P)/(P_(A)^(@))=chi_(B),` By putting values `0.018=((w_(B))/(M_(B)))/(w_(A)/(w_(B))+(w_(B))/(M_(B)))` `rArr 0.018=((3)/(M_(B)))/((3)/(M_(B))+(50)/(18))` by calculating `M_(B)~~60` |
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