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When a cylindrical wooden piece weighing 75 gwt is made to float in water, 25% of the total volume of the water. Find the extra force in gwt required to be applied on the piece downwardsso that the piece gets immersed in water completely |
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Answer» Solution :According to the law of floatation, weight of the floating body = weight of the LIQUID displaced `rArr("density of the body")/("density of the liquid")` `=("volume of the body inside liquid")/("total volume of the body")` Given `25%` of the body is above the water surface `rArr` FRACTION of the body inside water = `75%` `:.("Pwooden piece")/("Pwater")=75%` `rArr" Pwooden piece"=0.75" g cm"^(-3)` Given weight of the wooden piece = 75 gwt `:.` volume of the wooden piece `("75 gwt")/("0.75 g cm"^(-3))=100cm^(3)` volume of water displaced by the body = fraction of the body inside water X volume of the woodent piece `=0.75xx100=75cm^(3)` `:." remaining volume"=25cm^(3)` If the body has to be completely IMMERSED in water, the extra force required = weight of `25cm^(3)` of water = 25 gwt |
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