1.

When a cylindrical wooden piece weighing 75 gwt is made to float in water, 25% of the total volume of the water. Find the extra force in gwt required to be applied on the piece downwardsso that the piece gets immersed in water completely

Answer»

Solution :According to the law of floatation,
weight of the floating body = weight of the LIQUID displaced
`rArr("density of the body")/("density of the liquid")`
`=("volume of the body inside liquid")/("total volume of the body")`
Given `25%` of the body is above the water surface
`rArr` FRACTION of the body inside water = `75%`
`:.("Pwooden piece")/("Pwater")=75%`
`rArr" Pwooden piece"=0.75" g cm"^(-3)`
Given weight of the wooden piece = 75 gwt
`:.` volume of the wooden piece
`("75 gwt")/("0.75 g cm"^(-3))=100cm^(3)`
volume of water displaced by the body
= fraction of the body inside water X volume of the woodent piece
`=0.75xx100=75cm^(3)`
`:." remaining volume"=25cm^(3)`
If the body has to be completely IMMERSED in water, the extra force required
= weight of `25cm^(3)` of water = 25 gwt


Discussion

No Comment Found

Related InterviewSolutions