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When a light of frequency `v_(1)` is incident on a metal surface the photoelectrons emitted have twice the kinetic energy as did the photoelectron emitted when the same metal has irradiated with light of frequency `v_(2)`. What will be the value of threshold frequency?A. `v_(0)=v_(1)-v_(2)`B. `v_(0)=v_(1)-2v_(2)`C. `v_(0)=2v_(1)-v_(2)`D. `v_(0)=v_(1)+v_(2)`.

Answer» Correct Answer - C


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