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When a liquid that is immiscible with water was steam distilled at `952^(@)C` at a total pressure of `748` torr, the distillate contained `1.25g` of the liquid per gram of water. The vapour pressure of water is `648` torr at `95.2^(@)C`. What is the molar mass of liquid?A. `7.975 g//"mol"`B. `166 g//"mol"`C. `145.8g//"mol"`D. None of these |
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Answer» Correct Answer - A::B::C::D For two immischible liquid , `P_(A)^(@)=P_("total")-P_(H_(2^(O)))^(@)=748-648rArr100` `(W_(A))/(W_(B))=(P_(A)^(@)M_(A))/(P_(B)^(@)M_(B)) , M_(A)=(1.25)/(1)xx(648xx18)/(100)rArr145.8` |
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