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When a metal is irradiated with light of frequency `4.0 xx 10^(16)s^(-1)` the photo electrons emitted has six times the K.E as the K.E of photo electron emitted when the metal was irradiated with light of frequency `2.0 xx 10^(16)s^(-1)`. Calculate the critical frequency of the metal.A. `2.0 xx 10^(16)s^(-1)`B. `1.6xx 10^(16)s^(-1)`C. `3.0xx 10^(16)s^(-1)`D. `4.2 xx 10^(16)s^(-1)` |
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Answer» Correct Answer - B `(K.E_(2))/(K.E_(1)) = (v_(2)-v_(0))/(v_(1)-v_(0))` |
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