When a satellite is moving around the earth with velocity v, then to make the satellite escape, the minimum percentage increase in its velocity should be

When a satellite is moving around the earth with velocity v, then to m

1.	When a satellite is moving around the earth with velocity v, then to make the satellite escape, the minimum percentage increase in its velocity should be
Answer» Solution :The MAXIMUM orbital velocity of a satellite orbiting near its surface is `v_(0)= sqrt(gR)= (v_e)/(sqrt(2))` For the satellite to escape gravitational PULL the velocity must BECOME `v_e` But `v_e= sqrt(2)v_(0) =1.414 v_(0)= (1+0.414)v_(0)` This means that it has to increases 0.414 in 1 or 41.4%. The minimum increment is REQUIRED, as the velocity of satellite is maximum when it is near the earth.