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When electric transition occurs from higher energy state to lower energy state with energy difference equal to `Delta E` electron volts , the wavelkength of the line emitted is apporomately equal toA. `(12395)/(Delta E ) xx 10^(-10)m`B. `(12395)/(Delta E ) xx 10^(10)m`C. `(12395)/(Delta E ) xx 10^(-10)m`D. `(12395)/(Delta E ) xx 10^(10)m` |
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Answer» Correct Answer - A `lambda = (hc)/(Delta E) = (6.62 xx 10^(-34) J s xx 3 xx 10^(8) m s^(-1))/(E xx 1.602 xx 10^(-19) J)` `= 12395 xx 10^(-10)m` |
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