1.

When the angle between two vectorsof equal magnitude is 2pi//3, prove that tha magnitude of the resultant is equal to either.

Answer»

<P>

Solution :`R=(P^(2)+Q^(2)+2PQ cos THETA)^(1//2)`
`=(P^(2)+P^(2)+2P.P "cos"(2pi)/(3))^(1//2)`
`=[2P^(2)+2P^(2)((-1)/(2))]^(1//2)=P`


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