1.

When the electrolysis of acidified water is carried out : (a) What is the ratio of the volume of hydrogen produced to the volume of oxygen ? Give the equation for the discharge of ions at the two electrodes .

Answer»

Solution :(a) Volume of `H_(2) ` : Volume of `O_(2) = 2:1 `
(b) `4OH^(-) to 2H_(2)O +O__(2) +4e^(-)`
`2H^(+) + 2E^(-) to H_(2)`


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