1.

When `theta=(17pi)/3`, then the value of`(tan theta-cot theta)` is: (a) `2/sqrt3` (2) `-2/sqrt3` (3) `1/(2sqrt3)` (d) None

Answer» `theta=17/3pi=(5+2/3)pi`
`=6pi-pi/3`
`tantheta-cottheta=tantheta-1/tantheta`
`tan(6pi-pi/3)-1/tan(6pi-pi/3)`
`tan(-pi/3)-1/tan9-pi/3)`
`-sqrt3-1/-sqrt3`
`2/sqrt3`
Option B is correct.


Discussion

No Comment Found