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When `theta=(17pi)/3`, then the value of`(tan theta-cot theta)` is: (a) `2/sqrt3` (2) `-2/sqrt3` (3) `1/(2sqrt3)` (d) None |
Answer» `theta=17/3pi=(5+2/3)pi` `=6pi-pi/3` `tantheta-cottheta=tantheta-1/tantheta` `tan(6pi-pi/3)-1/tan(6pi-pi/3)` `tan(-pi/3)-1/tan9-pi/3)` `-sqrt3-1/-sqrt3` `2/sqrt3` Option B is correct. |
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