1.

When three resistors, each of resistance R, are connected in parallel, the equivalent resistance is found out to be 10 Omega. R must be …………………. .

Answer»

`10 Omega`
`20 Omega`
`30 Omega`
` 5 Omega`

SOLUTION :`1/(R.) = 1/R_1 + 1/R_2 + 1/R_3`
Now. `R_1 = R_2 =R_3 =R`
`:. 1/(R.) = 1/R + 1/R + 1/R = 3/R`
`:. R = 3R. = 3(10) =30Omega`


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