1.

When two moles of hydrogen are heated with two moels of iodine, 2.96 moles of hydrogen iodide are formed. Calculate K_(c) for the reaction of formation of hydrogen iodide.

Answer»

Solution :`H_(2)(G)+I_(2)(g) HARR 2HI(g)`
At equilibrium, `2-X""2-x""2X`
`2x=2.96`
`x=(2.96)/(2)=1.48`
`K_(c)=([HI]^(2))/([H_(2)][I_(2)])=((2x)^(2))/((2-1.48)(2-1.48))=(4XX(1.48)^(2))/(0.52xx0.52)=32.4`


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