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Which is the correct relationship-A. `E_(1)` of `H=1//2E_(2)` of `He^(+)=1//3E_(3)`of `Li^(2+)=1//4E_(4)`of `Be^(3+)`B. `E_(1)(H)=E_(2)(He^(+))=E_(3)(Li^(2+))=E_(4)(Be^(3+))`C. `E_(1)(H)=2E_(2)(He^(+))=3E_(3)(Li^(2+))=4E_(4)(Be^(3+))`D. No relation |
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Answer» Correct Answer - B `E_(n) = - 13.6 xx(Z^(2))/(n^(2))` `E_(1)(H) =-13.6xx(1)/(1)=-13.6eV` `E_(2)(He^(+))=-13.6xx(4)/(4)=-13.6eV` `E_(3)(Li^(2+))=-13.6xx(3^(2))/(3^(2))=-13.6eV` `E_(4)(Be^(3+))=-13.6xx(4^(2))/(4^(2))=-13.6eV` `therefore` Ans `B` |
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