1.

Which one of the following will have largest number of atoms? (i) 1gAu(s) (ii) 1gNa(s) (iii) 1gLi(s) (iv) 1g" of "Cl_(2)(g) ("Atomic masses : Au = 197, Na = 23, Li = 7, Cl = 35.5 amu")

Answer»

SOLUTION :(i)`"1 g Au"=(1)/(197)" mol"=(1)/(197)xx6.02xx10^(23)" ATOMS"`
(ii) `"1 g Na"=(1)/(23)" mol"=(1)/(23)xx6.023xx10^(23)" atoms"`
(iii) `"1 g Li "=(1)/(7)" mol"=(1)/(7)xx6.02xx10^(23)" atoms"`
(IV) `"1 g Cl"_(2)=(1)/(71)" mol"=(1)/(71)xx6.02xx10^(23)" MOLECULES"=(2)/(971)xx6.02xx10^(23)" atoms."`
Thus, 1 g of Li has the largest number of atoms.


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