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Which one of the following will have largest number of atoms? (i) 1gAu(s) (ii) 1gNa(s) (iii) 1gLi(s) (iv) 1g" of "Cl_(2)(g) ("Atomic masses : Au = 197, Na = 23, Li = 7, Cl = 35.5 amu") |
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Answer» SOLUTION :(i)`"1 g Au"=(1)/(197)" mol"=(1)/(197)xx6.02xx10^(23)" ATOMS"` (ii) `"1 g Na"=(1)/(23)" mol"=(1)/(23)xx6.023xx10^(23)" atoms"` (iii) `"1 g Li "=(1)/(7)" mol"=(1)/(7)xx6.02xx10^(23)" atoms"` (IV) `"1 g Cl"_(2)=(1)/(71)" mol"=(1)/(71)xx6.02xx10^(23)" MOLECULES"=(2)/(971)xx6.02xx10^(23)" atoms."` Thus, 1 g of Li has the largest number of atoms. |
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