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Who Will spend more electrical energy ? 500 W TV set in 30 mins, or 600W heater in 20 mins ? |
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Answer» `THEREFORE"Energy "="Power"xx"time"` `E_(1)=500xx30xx60=900xx10^(3)J` For HEATER: Power = 600W, Time = 20 min = `20xx60s` `therefore"Energy "(E_(2))=600xx20xx60=720xx10^(3)J` COMPARING `E_(1) and E_(2), E_(1)gt E_(2)` `therefore"Energy spend by T.V. set "(E_(1))` is greater. |
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