InterviewSolution
Saved Bookmarks
| 1. |
With what velocity should an `alpha ` paricle travel towards the nucleus of a copper atom so as to arrive at a distance `10^(-13)m` from the nucleus of the copper atom? |
|
Answer» `(1)/2m_(alpha)v_(alpha)^(2)=(kz_(1)z_(2))/(r_("min")^(2))=(k(2e)k(63e))/r_("min")^(2)` `v_(alpha)=(k(2e)(63e))/(m_(alpha).r^(2)_("min")` `v_(alpha)=sqrt((2k.2e.63e)/(m_(alpha).r_("min")^(2)))=6.3xx10^(6)m//s` |
|