InterviewSolution
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InterviewSolution
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Without using trignometric tables, prove that : (i) sin 53^@cos 37^@+cos 53^@sin 37^@=1 (ii) cos 54^@cos 36^@-sin 54^@sin 36^@=0 (iii) sec 35^@sin 20^@+cos 20^@cosec 70^@=2 (iv) sin 35^@sin 55^@-cos 35^@cos 55^@=0 (v) (sin 72^@+cos 18^@)(sin 72^@-cos 18^@)=0 (vi) tan 48^@tan 23^@tan 42^@tan 67^@=1 |
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Answer» SOLUTION :`(IV) LHS =sin 35^@sin(90^@-35^@)-COS 35^@cos(90^@-35^@)=sin 35^@cos 35^@-sin 35^@cos 35^@=0` `(V) LHS =sin^2 72^@-cos^2 18^@=sin ^2 72^@-cos^2(90-72^@)=sin^2 72^@-sin ^2 72^@=0`. |
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