1.

Write a value of ∫ cos4x sin x dx.

Answer»

Let cosx = t 

Differentiating on both sides we get, 

- sinx dx = dt 

Substituting above equation in ∫cos4x sinx dx we get, 

= ∫- t4 dt

\(-\frac{t^5}{5}\) + c

\(-\frac{cos^5x}{5}\) + c



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