InterviewSolution
Saved Bookmarks
| 1. |
Write a value of ∫ cos4x sin x dx. |
|
Answer» Let cosx = t Differentiating on both sides we get, - sinx dx = dt Substituting above equation in ∫cos4x sinx dx we get, = ∫- t4 dt = \(-\frac{t^5}{5}\) + c = \(-\frac{cos^5x}{5}\) + c |
|