1.

Write a value of ∫ sin3x cosx dx.

Answer»

Let sin x = t 

Differentiating on both sides we get, 

cosx dx = dt 

Substituting above equation in ∫sin3x cosx dx we get, 

= ∫t3 dt

\(\frac{t^4}{4}\) + c

\(\frac{sin^4x}{4}\) + c



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