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Write a value of ∫ sin3x cosx dx. |
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Answer» Let sin x = t Differentiating on both sides we get, cosx dx = dt Substituting above equation in ∫sin3x cosx dx we get, = ∫t3 dt = \(\frac{t^4}{4}\) + c = \(\frac{sin^4x}{4}\) + c |
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