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Write a value of ∫ tan3xsec2xdx. |
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Answer» Given, ∫ tan3xsec2xdx let tan x = t Differentiating on both sides we get, sec2x dx = dt Substituting above equation in ∫tan3x sec2x dx we get, = ∫t3 dt = \(\frac{t^4}{4}\)+ c = \(\frac{tan^4x}{4}\) + c |
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