1.

Write the chemical equation of the reaction with an example each in which the following change has taken place: (i) Change in colour (ii) Change in temperature (iii) Formation of precipitate.

Answer»

SOLUTION :(i) Change in colour : Reaction between lead nitrate solution and potassium iodide solution.
`Pb(NO_(3))_(2)(aq)+2KIrarrPbI_(2)(S)+2KNO_(3)(aq)`
In this reaction, colour changes from colourles to yellow.
(ii) Change in temperature : ACTION of DILUTE sulphuric acid on zinc.
`Zn(S)+H_(2)SO_(4)(aq)rarrZnSO_(4)(aq)+H_(2)`
In this reaction, heat is evolved
(iii) Formation of precipitate : Action of barium CHLORIDE on SODIUM sulphate .
`BaCl_(2)(aq)+Na_(2)SO_(4)(aq)rarrBaSO_(4)(S)+2NaCl(aq)(ppt.)`


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