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Write the chemical equation of the reaction with an example each in which the following change has taken place: (i) Change in colour (ii) Change in temperature (iii) Formation of precipitate. |
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Answer» SOLUTION :(i) Change in colour : Reaction between lead nitrate solution and potassium iodide solution. `Pb(NO_(3))_(2)(aq)+2KIrarrPbI_(2)(S)+2KNO_(3)(aq)` In this reaction, colour changes from colourles to yellow. (ii) Change in temperature : ACTION of DILUTE sulphuric acid on zinc. `Zn(S)+H_(2)SO_(4)(aq)rarrZnSO_(4)(aq)+H_(2)` In this reaction, heat is evolved (iii) Formation of precipitate : Action of barium CHLORIDE on SODIUM sulphate . `BaCl_(2)(aq)+Na_(2)SO_(4)(aq)rarrBaSO_(4)(S)+2NaCl(aq)(ppt.)` |
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