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Write the following squares of binomials as trinomials:(i) (9a + 1/6)2(ii) (x + x2/2)2(iii) (x/4 – y/3)2 |
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Answer» (i) (9a + 1/6)2 = (9a)2 + 2 (9a) (1/6) + (1/6)2 = 81a2 + 3a + 1/36 (ii) (x + x2/2)2 = (x)2 + 2 (x) (x2/2) + (x2/2)2 = x2 + x3 + 1/4x4 (iii) (x/4 – y/3)2 (x/4)2 – 2 (x/4) (y/3) + (y/3)2 = 1/16x2 – xy/6 + 1/9y2 |
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