1.

Write the IUPAC name of the compound CH_3 - CH_2 - undersetoverset(|)(COOH)(C)H - CH_3

Answer»

Solution :(a) There are 4 C atoms in the chain involving -COOH GROUP, therefore, the root word is .but..
(b) Only C-C bonds appear between C atoms in the chain, therefore, primary SUFFIX is! .ane.. Thus,
Base name = root word + primary suffix = but + ane = butane
(c) There is -COOH group in the chain, therefore, secondary suffix is .oic acid..
(d) There is one methyl radical `(-CH_3)` at CARBON 2 of the chain, therefore, the prefix is .2-methyl..
Thus, the IUPAC name of the given compound is derived as:
Prefix + Base name -e + Secondary suffix
2-Methyl + butane - e + oic acid = 2-Methylbutanoic acid


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