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X g of CO_(2) is prepared by thereaction of CaCO_(3) and HCl. How many grams of oxygen will be liberated, if X grams of CO_(2) completely take part intheprocess of photosynthesis ?144 g of water is produced in the first reaction. Equation for photosynthesis is CO_(2) + H_(2)O to C_(6)H_(12)O_(6)+O_(2) |
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Answer» Solution :`CaCO_(3) + 2HCl to CaCl_(2) + CO_(2) + H_(2)O` `6CO_(2) + 6H_(2)O to C_(6)H_(12)O_(6) + 6O_(2)` Number of moles of WATER formed in thefirst reaction = `(144)/18 = 8` Number of moles of `CO_(2)` produced= 8 Number of moles of oxygen produced by using8 moles `CO_(2)` is 8 . WEIGHT of oxygen liberated ` = 32 xx 8 = 256` g |
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