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x के सापेक्ष (Differentiate) `tan^(-1)((sqrt(1+x^(2))-1)/(x))` (w,r,t.x) को अवकलित करें । |
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Answer» माना कि `y=tan^(-1)((sqrt(1+x^(2)-1))/(x))` `thereforey=tan^(-1)((sqrt(1+tan^(2)theta)-1)/(tantheta)) " " [x tan theta` रखने पर] `=tan^(-1)((sectheta-1)/(tantheta))=tan^(-1)((1-costheta)/(sintheta))` `=tan^(-1)((2" sin"^(2)(theta)/(2))/(2 " sin"(theta)/(2)"cos"(theta)/(2)))=tan^(-1)("tan"(theta)/(2))=(theta)/(2)=(1)/(2)tan^(-1)x` `therefore(dy)/(dx)=(1)/(2)*(1)/(1+x^(2))` |
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