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`y=sin^(-1)[sqrt(x-a x)-sqrt(a-a x)]` |
Answer» Correct Answer - `(1)/(2sqrt(x(1-x)))` `y=sin^(-1)[sqrt(x-ax)-sqrt(a-ax)]` `=sin^(-1)[sqrt(x)sqrt(1-a)-sqrt(a)sqrt(1-x)]` `=sin^(-1)[sqrt(x)sqrt(1-(sqrt(a))^(2))-sqrt(a)sqrt(1-(sqrt(x))^(2))]` `=sin^(-1)sqrt(x)-sin^(-1)sqrt(a)` `therefore" "(dy)/(dx)=(1)/(sqrt(1-x))xx(1)/(2sqrt(x))` |
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