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यदि |a|=10, |b|=2 तथा a.b=12 है तो `|axxb|` का मान हैA. 16B. 256C. `-16`D. `-256` |
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Answer» Correct Answer - A यहाँ `|a|=10,|b|=2 a.b=12` [दिया है] `therefore |a xx b|=|a| |b| sin theta` `therefore |a xx b|^(2)=|a|^(2) |b|^(2) sin^(2) theta` ` =|a|^(2) |b|^(2)(1-cos^(2)theta)` ` =|a|^(2) |b|^(2)|a|^(2) |b|^(2) cos^(2)theta` ` =|a|^(2) |b|^(2)-(a.b)^(2)` `[therefore a.b=|a||b| cos theta]` `=100xx4-144=256` `|a xx b|=16` |
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